Answer:
Isosceles [A triangle that has two equal arms is called an isosceles triangle]
Step-by-step explanation:
∠BAC=∠ACB
thus, AB=BC
Prove,
∠BAC=∠ACD=50° ;[AB║DE]
∠ABC=∠BCE=80° ;[AB║DE]
∠ACD+∠ACB+∠BCE = 180°
50°+∠ACB+80° = 180°
∠ACB = 180°- 130° = 50°
