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How much heat, in kilojoules, must be added to a 580 g aluminum pan to raise its temperature from 25∘C to 150∘C?
---The specific heat capacity for aluminum is 0.897 J/g∘C.
---Round the answer to two significant figures.

Respuesta :

Answer:

Q = 65 kJ

Explanation:

Given that,

Mass, m = 580 g

Initial temperature, [tex]T_i=25^{\circ} C[/tex]

Final temperature, [tex]T_f=150^{\circ} C[/tex]

The specific heat capacity for aluminum is 0.897 J/g°C

We need to find the heat added to the aluminium pan so that its heat raised to a temperature from 25°C to 150°C. It is given by :

[tex]Q=mc\Delta T\\\\Q=580\ g\times 0.897\ J/g^{\circ} C\times (150-25)^{\circ} C\\\\Q=65032.5\ J[/tex]

or

Q = 65.03 kJ

or

Q = 65 kJ

Hence, the heat added to the pan is 65 kJ.

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