Answer:
(8, 1)
Step-by-step explanation:
Lets say you had 2 points, (x₁, y₁) and (x₂, y₂). The midpoint of these two lines would be:
[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]
Lets use (6, -2) for (x₁, y₁) and (10, 4) for (x₂, y₂):
[tex](\frac{6+10}{2},\frac{(-2)+4}{2})=(\frac{16}{2},\frac{2}{2})=(8,1)[/tex]
So the midpoint of AB would be (8, 1).
I hope you find my answer helpful.
