burbur420420
burbur420420 burbur420420
  • 14-09-2020
  • Mathematics
contestada

If h = -19 and j = 16, what is
[tex] \sqrt{j - h} [/tex]
​

Respuesta :

m4r31
m4r31 m4r31
  • 14-09-2020
Add 16 and 19 in the root.
Answer is root of 35.
Answer Link
ZJSG09112007
ZJSG09112007 ZJSG09112007
  • 14-09-2020

Answer:

[tex]\sqrt{35}[/tex]

Step-by-step explanation:

h =-19

j =16

[tex]\sqrt{j-h} = ?[/tex]

Substitute values into the given equation

[tex]\sqrt{16-(-19)} \\\\\mathrm{Apply\:rule}\:-\left(-a\right)=a\\\\=\sqrt{16+19}\\\\\mathrm{Add\:the\:numbers:}\:16+19=35\\\\=\sqrt{35}[/tex]

Answer Link

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