Respuesta :

RajatDutt

Answer:

In ∆ABD and ∆ACD

<BAD =<CAD ( each are half of <A )

<D=<D ( each equal to 90°)

AD = AD ( common)

So ∆ ABD is congruent to ∆ ACD.

Then AB =AC (by C.P.C.T)

Hence,∆ABC is an iso - sceles triangle.

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