Answer:
The force applied on the big piston is 1306.67 N
Explanation:
Given;
force applied on small piston, Fâ = 200 N
diameter of the small piston, dâ = 4.37 cm
radius of the small piston, râ = dâ/2 = 2.185 cm
Area of the small piston, Aâ = Ďrâ² = Ď(2.185 cm)² = 15 cm²
Area of the big piston, Aâ = 98 cm²
The pressure of the piston is given by;
[tex]P = \frac{F}{A} \\\\\frac{F_1}{A_1} = \frac{F_2}{A_2}\\\\ F_2 = \frac{F_1A_2}{A_1}[/tex]
Where;
Fâ is the force on big piston
[tex]F_2 = \frac{200*98}{15} \\\\F_2 = 1306.67 \ N[/tex]
Therefore, the force applied on the big piston is 1306.67 N