Answer:
b. pH=12
Explanation:
Step 1: Given data
Concentration of NaOH: 0.01 mol/dm³ = 0.01 mol/L = 0.01 M
Step 2: Write the reaction for the dissociation of NaOH
NaOH is a strong base that dissociates according to the following equation.
NaOH(aq) ⇒ Na⁺(aq) + OH⁻(aq)
The molar ratio of NaOH to OH⁻ is 1:1. Then, the concentration of OH⁻ is 0.01 M.
Step 3: Calculate the pOH
pOH = -log [OH⁻] = -log 0.01 = 2
Step 4: Calculate the pH
We will use the following expression.
pH + pOH = 14
pH = 14 - pOH = 14 -2 = 12
