Answer:
C. 101.5°C
Explanation:
The computation of the boiling point of a solution is shown below:
As we know that
[tex]\Delta T = i K_bm[/tex]
where,
i = Factor of Van’t Hoff i.e 2KBr
K_b = Boiling point i.e 0.512° C
m = molality [tex]= \frac{Moles\ of\ solute}{Solvent\ mass}[/tex]
Now place the values to the above formula
So, the boiling point is
[tex](T - 100^\circ C) = 2\times 0.512^\circ \times \frac{3.00\ ml}{2.00\ kg}[/tex]
After solving this, the t is
= 100° C + 1.536° C
= 101.536° C
Hence, the correct option is C.
