Answer:
The average current will be "17.69 nA".
Explanation:
The given values are:
Charge,
q = 9.2 pC
Time,
t = 0.52ms
The equivalent circuit of the cell surface is provided by:
⇒  [tex]i_{avg}=\frac{charge}{t}[/tex]
Or,
⇒  [tex]i_{avg}=\frac{q}{t}[/tex]
On substituting the given values, we get
⇒     [tex]=\frac{9.2\times 10^{-12}}{0.52\times 10^{-3}}[/tex]
⇒     [tex]=17.69^{-9}[/tex]
⇒     [tex]=17.69 \ nA[/tex]
