How many moles of phosphoric acid are required to neutralize 7.2 mol of potassium hydroxide?

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jeracoo jeracoo · Answer 1 · 2020-06-15T02:12:21+02:00

Answer:

2.4 Moles of Phosphoric acid are required to neutralize 7.2 moles of potassium hydroxide

Explanation:

Phosphoric acid = Formula: H3PO4

Potassium hydroxide = Formula: KOH

H3PO4 + 3KOH = K3PO4 + 3H2O

Ratio 1:3

7.2 mol Potassium hydroxide = Formula: KOH

7.2/3 = 2.4 Mol Phosphoric acid = Formula: H3PO4

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