Respuesta :

osikbro

Answer:

[tex]\dfrac{1+1.561i}{4}, \dfrac{1-1.561i}{4}[/tex]

Step-by-step explanation:

[tex]6x^2-3x+2=0[/tex]

Using the quadratic formula:

[tex]x=\dfrac{3\pm\sqrt{9-48}}{12}= \\\\\\\dfrac{1+1.561i}{4}, \dfrac{1-1.561i}{4}[/tex]

Hope this helps!

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