Answer:
The coordinates of P' are [tex](-\frac{9}{4},\frac{3}{2})[/tex]
Step-by-step explanation:
Given a point (x,y). If we have a dilation by a scale factor of r, centered at the origin, we have that the coordinates of (x,y) in the new system is given by (r*x,r*y).
Assumign that this dilation is centered at the origin, then if P is the point (-6,4) then the point P' is [tex](-6\cdot \frac{3}{8},4\cdot \frac{3}{8}) = (-\frac{9}{4},\frac{3}{2})[/tex]
