answer
[tex]3x^{2}+15x+12=0[/tex]
Step-by-step explanation:
equation: 3x(x + 4) + 3(x + 4) = 0
distribute 3x into your (x+4)
that'll give you : [tex]3x^{2} +12x+3(x+4)=0[/tex]
now distribute your 3 into your (x+4)
that'll give you [tex]3x^{2} +12x+3x+12=0[/tex]
now combine like terms and you'll end up with
[tex]3x^{2} +15x+12=0[/tex]
hope this helps
