Respuesta :
Answer: Β The correct option is
(A) Β Q'(0,-4), P'(β7, -6) and R'(β1, -2).
Step-by-step explanation: Β Given that the vertices of triangle QPR are Q(β4,0), P(β6, 7), and R(β2, 1). The triangle is rotated 90Β° counterclockwise about the origin to form Q' P' R'.
We are to find the co-ordinates of the vertices of triangle Q'P'R'.
We know that
if a point (x, y) is rotated 90Β° counterclockwise about the origin, then its co-ordinates becomes
(x, y) Β β Β (-y, x).
So, the vertices of triangle QPR changes as follows :
Q(-4, 0) β Q' (0, -4),
P(-6,7) Β β Β P'(-7, -6)
and
R(-2, 1) Β β Β R'(-1, -2).
Thus, the co-ordinates of the vertices of triangle Q'P'R' are Q'(0,-4), P'(β7, -6) and R'(β1, -2).
Option (A) is CORRECT.