Answer:
4x / (2x^2+1)
Step-by-step explanation:
g(x)=ln(2x^2+1)
Using u substitution
u= 2x^2 +1
du = 4x dx
g'(x) = d/du ( g(u) du)
We know that the derivative of ln(u) = 1/u since this is always positive
= 1/ u* du
Substituting x back into the equation
g'(x) = 1/(2x^2+1) * 4x
= 4x / (2x^2+1)
