emiliap227 emiliap227
  • 15-03-2020
  • Mathematics
contestada

Y=x^2+2;D:-1, 0, 1, 2, 3

Respuesta :

bhuvna789456
bhuvna789456 bhuvna789456
  • 23-03-2020

For the various values of X the values of Y are given as follows

X=-1; Y=3

X=0; Y=2

X=1; Y=3

X=2; Y=6

X=3; Y=11

Step-by-step explanation:

Step 1:

Let us consider the given expression as

[tex]Y= X^{2} + 2[/tex]

Step 2:

Let us discuss the value of Y for the various values of X

If X = -1, Y = (-1)² + 2 = 3

If X = 0, Y = (0)² + 2 = 2

If X = 1, Y = (1)² + 2 = 3

If X = 2, Y = (2)² + 2 = 6

If X = 3, Y = (3)² + 2 = 11

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