Answer:
P1(0 , -1)
Step-by-step explanation:
Let (x1 , y1) be the coordinates of P1 the image of P(x , y)
[tex]\left \{ {{x_{1} =x-6} \atop {y_{1} =y-1}} \right. \\\\then\\\\\left \{ {{x_{1} =6-6 = 0} \atop {y_{1} =0-1 = -1}} \right.\\\\then\\\\P_{1} (0 , -1)[/tex]
