Answer: The experimental van't Hoff factor is 1.21
Explanation:
The expression for the depression in freezing point is given as:
[tex]\Delta T_f=iK_f\times m[/tex]
where,
i = van't Hoff factor = ?
[tex]\Delta T_f[/tex] = depression in freezing point = 0.225°C
[tex]K_f[/tex] = Cryoscopic constant = 1.86°C/m
m = molality of the solution = 0.100 m
Putting values in above equation, we get:
[tex]0.225^oC=i\times 1.86^oC/m\times 0.100m\\\\i=\frac{0.225}{1.86\times 0.100}=1.21[/tex]
Hence, the experimental van't Hoff factor is 1.21
