Answer:
A
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Table 1
Calculate m using the slope formula
m = (yβ - yβ ) / (xβ - xβ )
with (xβ, yβ ) = (- 1, - 1) and (xβ, yβ ) = (5, 11) β 2 ordered pairs from the table
m = [tex]\frac{11+1}{5+1}[/tex] = [tex]\frac{12}{6}[/tex] = 2, thus
y = 2x + c β is the partial equation
To find c substitute (5, 11) into the partial equation
11 = 10 + c β c = 11 - 10 = 1
y = 2x + 1 β equation representing Table 1
Table 2
let (xβ, yβ ) = (2, 8) and (xβ, yβ ) = (- 4, - 10)
m = [tex]\frac{-10-8}{-4-2}[/tex] = [tex]\frac{-18}{-6}[/tex] = 3, thus
y = 3x + c β is the partial equation
To find c substitute (2, 8) into the partial equation
8 = 6 + c β c = 8 - 6 = 2
y = 3x + 2 β equation representing Table 2