mikemoss4328 mikemoss4328
  • 14-01-2020
  • Mathematics
contestada

Find an equation of the plane that passes through the origin and its perpendicular to the vector [1,-2,5]

Respuesta :

GreatB GreatB
  • 15-01-2020

Answer:

x - 2y + 5z = 0

Step-by-step explanation:

The standard equation is of the form, Ax + By + Cz = 0

The equation of the plane that passes through the origin(0, 0, 0)  and is perpendicular to [1, -2, 5] is

A = 1, B = -2, C = 5

x = y = z = 0 (at origin)

A(x-0) + B(y-0) + C(z-0) = 0

(x - 0) -2(y-0) + 5(z-0) = 0

x - 2y + 5z = 0

Answer Link

Otras preguntas

l=3cm, w=1cm, h=3cm what is the surface area of the rectangular prism​
What's a very complex equation that equals 3
Salts and sugars work to preserve food by creating a
PLEASE HELP ME !!!!!! WILL GIVE POINTS OUT 60 POINTS
Jack is going to the fair. The fair charges $10 to enter and $0.25 per ticket. How much will be spent by Jack? t = tickets 0.25 + 10 10 + 0.25t​
What process must happen for clouds to form?
help me its geometry
why Ads pls take off Ads
Secure email technique that provides confidentiality, along with authentication, integrity, and non-repudiation. It uses a centralized trust model where users g
Please help explanation if possible