ml7300398
ml7300398 ml7300398
  • 04-01-2020
  • Mathematics
contestada

Could someone help me with this exercise?

Could someone help me with this exercise class=

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 04-01-2020

Answer:

  • 5%: 66 2/3 mL
  • 6.5%: 133 1/3 mL

Step-by-step explanation:

Let x represent the number of milliliters of 6.5% vinegar required. Then the total amount of acetic acid in the mix is ...

  6.5%·x + 5%(200 -x) = 6%·200

  1.5x = 200 . . . . . . . . . . . . . multiply by 100, subtract 1000

  x = 200/1.5 = 133 1/3 . . . . mL of 6.5% vinegar

  200-x = 66 2/3 . . . . . . . . . mL of 5% vinegar

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