In a survey, 36% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result to be too high, so she randomly selected 240 pet owners and discovered that 79 of them spoke to their pet on the telephone. Does the veterinarian have a right to be skeptical? Use the alphaequals0.05 level of significance.Use technology to find the P-value.P-value=???(Round to three decimal places as needed.)

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windyyork windyyork · Answer 1 · 2019-11-14T07:36:41+01:00

Answer: p value is 0.1685.

Step-by-step explanation:

Since we have given that

The survey is conducted on a random sample of 240 pet owners.

Out of them, number of owners spoke to their pet on telephone = 79

n = 240

x = 79

[tex]\hat{p}=\dfrac{x}{n}=\dfrac{79}{240}=0.33[/tex]

Our hypothesis would be

[tex]H_0:p=0.5\\\\H_1:p>0.5[/tex]

Formula for test statistic would be

[tex]\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\=\dfrac{0.33-0.36}{\sqrt{\dfrac{0.36(1-0.36)}{240}}}\\\\=-0.96[/tex]

p value = 0.1685

Hence, p value is 0.1685.