Answer:
The answer to your question is below
Step-by-step explanation:
Data
3 shirts and 2 pair of pants
cost = Â $300
x = shirt price
y = pants price
a) Â Â Â 3x + 2y = 300
b) Â Â Â 2y = - 3x + 300
    y = -3/2 x + 300/2
    y = -3/2 x + 150
c) Â Â Â y = -3/2 (20) + 150
    y = -30 + 150
    y = 120  each of the pants costs $120
d) Â Â Â 3x + 2y = 300
 if y = 0
    3x = 300
    x = 300/3
    x = 100        It could be the highest cost of a shirt
e) Â Â Â 3x + 2y = 300
if x = 0
   3(0) + 2y = 300
   2y = 300
   y = 300/2
   y = 150        it could be the highest cost of a pair of pants.