Answer:c
Step-by-step explanation:
Given
[tex]m\left ( x\right )=x+\frac{5}{x-1}[/tex]
and [tex]n\left ( x\right )=x-3[/tex]
m of n is given by replacing x in [tex]m\left ( x\right )[/tex] by x-3
[tex]m\left ( n\left ( x\right )\right )=x-3+\frac{5}{x-3-1}=x-3+\frac{5}{x-4}[/tex]
[tex]m\left ( n\left ( x\right )\right )[/tex] can take any value of x except x=4 because at x=4 function is not defined
and [tex]h\left ( x\right )=\frac{11}{x-4}[/tex] is also not defined for x=4 and can take any value of x
