Answer:
pH of solution is 3.80
Explanation:
- Formic acid an weak acid and formate is conjugate base of formic acid
- Hence solution containing formic acid and formate acts as a buffer.
- According to Henderson-Hasselbalch equation for a buffer consist of an weak acid (formic acid) and it's conjugate base (formate)-
[tex]pH=pK_{a}(formic acid)+log(\frac{C_{formate}}{C_{formic acid}})[/tex]
where, C stands for concentration
- [tex]pK_{a}[/tex] of formic acid 3.75
So, [tex]pH=3.75+log(\frac{0.055}{0.049})=3.80[/tex]
