Answer:
The answer is [tex] 3.994 \times 10^{13}\ electrons[/tex]
Explanation:
The amount of negative charge that must be removed is
[tex]\Delta = Final\ charge - initial\ Charge = 2.6 - (-3.8) = 6.4 \ \mu C = 6.4 \times 10^{-6}\ C[/tex]
and the charge of one electron is
[tex]1 e = 1.60217662\times 10^{-19} \ C[/tex]
So the amount of electrons we need to remove is
[tex]x = \frac{6.4 \times 10^{-6}}{1.60217662\times 10^{-19}} \approx 3.994 \times 10^{13}\ electrons[/tex]
