denaw8529 denaw8529
  • 13-09-2019
  • Chemistry
contestada

Consider water at 1400 kPa and 200 C. What is the specific volume (in m3 /kg)?

Respuesta :

gbustamantegarcia054 gbustamantegarcia054
  • 16-09-2019

Answer:

Vw = 2.80907 E-3 m³/Kg

Explanation:

specific volume is the inverse of density:

⇒ Vw = 1 / ρ

∴ water at:

⇒ P = 1400 KPa * ( 1000 Pa / KPa ) = 1400000 Pa

⇒ T = 200°C = 473 K

Water at these conditions is found as saturated steam, specific volume would be:

⇒ Vw = R*T / P

∴ R = 8.3144 Pa.m³/ Kg.K

⇒ Vw = (( 8.3144 ) * ( 473)) / 1400000

⇒ Vw = 2.80907 E-3 m³/Kg

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