Answer:
11
Step-by-step explanation:
Another way you can think is as
[tex] \frac{AD}{AB} = \frac{AD}{2AD} = \frac{1}{2} [/tex]
Given D & E are mid points of AB & AC
So, DE must be parallel to BC
By the property of similar triangles
ADE ~ ABC
[tex] \frac{DE}{BC} = \frac{1}{2} \\ \frac{DE}{22} = \frac{1}{2 } \\ DE = \frac{22}{2} = 11[/tex]
Hope it helps too ;))
