For this case we must solve the following inequality:
[tex]38 <4x + 3 + 7-3x[/tex]
We add similar terms to the right side of inequality:
[tex]38 <4x-3x + 3 + 7\\38 <x + 10[/tex]
We subtract 10 from both sides of the inequality:
[tex]38-10 <x\\28 <x[/tex]
Thus, the solution will be given by all values of "x" greater strict to 28.
Answer:
[tex]x> 28[/tex]
