For this case we have a function of the form [tex]y = f (x)[/tex], where:
[tex]f (x) = \frac {5 + x} {6 + 3x}[/tex]
We must evaluate the function at[tex]x = a-1[/tex]
So:
[tex]g (a-1) = \frac {5+ (a-1)} {6 + 3 (a-1)}\\g (a-1) = \frac {5 + a-1} {6 + 3a-3}\\g (a-1) = \frac {4 + a} {3 + 3a}[/tex]
Thus, the value of the function is:
[tex]\frac {4 + a} {3 + 3a}[/tex]
Answer:
[tex]g (a-1) = \frac {4 + a} {3 + 3a}[/tex]
