Answer:
b)0, yes
Step-by-step explanation:
Given:
Vectors (4,8) . (6,-3)
Finding inner product of vectors:
= 4x6 + 8x-3
=24-24
=0
Now to check the angle between them using formula a.b=|a|.|b|cosθ
|a|= [tex]\sqrt{4^{2} +8^{2} } \\\sqrt{16+64}[/tex]
=8.9
|b|=[tex]\sqrt{6^{2} +(-3)^{2} } \\\sqrt{36+9}[/tex]
=6.7
Putting values of a.b=0 and |a|=8.9, |b|=6.7 in a.b=|a|.|b|cosθ we get,
0= 8.9(6.7)cosθ
cosθ =0
θ=90 degrees
Hence the two vectors are perpendicular !
