Answer: Option A.
Step-by-step explanation:
To find the product you need to multiplicate [tex]-\frac{1}{2}y[/tex] by [tex](2y^3-8)[/tex]
Apply Distributive property.
Remember the Product of powers property:
[tex](b^a)(b^c)=b^{(a+c)}[/tex]
Remember the multiplication of signs:
[tex](-)(-)=+\\(+)(+)=+\\(-)(+)=-[/tex]
Then the product is:
[tex]-\frac{1}{2}y(2y^3-8)=-\frac{2}{2}y^4+\frac{8}{2}=-y^4+4[/tex]
Option A is the correct answer.
