Answer:
[tex]\frac{3}{3x-1}[/tex]
Step-by-step explanation:
[tex]\frac{f(x)}{g(x)}\\\frac{6x^2+36}{6x^2+34x-12}\\\frac{6(x^2+6)}{2(3x^2+17x-6)}[/tex]Factor out a 6 from the numerator and 2 from the denominator
[tex]\frac{3(x^2+6)}{3x^2+17x-6}[/tex] 2 in the denominator divides the 6 in the numerator
[tex]\frac{3(x+6)}{(3x-1)(x+6)}[/tex] factor the denominator, let me know if you need help with this
[tex]\frac{3}{3x-1}[/tex] the (x+6)s cancel
