Answer: [tex]log_3(\frac{k^7*m^6}{n^9})[/tex]
Step-by-step explanation:
By the properties of exponents you have that:
[tex]log(a)+log(b)=log(ab)\\\\log(a)-log(b)=log(\frac{a}{b})\\\\log(b)^a=alog(b)[/tex]
Therefore, keeping the properties on mind, you can simplify as following:
[tex]log_3(k)^7+log_3(m)^6-log_3(n)^9\\\\log_3(k^7*m^6)-log_3(n)^9\\\\log_3(\frac{k^7*m^6}{n^9})[/tex]
