For this case we have to:
[tex]2m-6 = 8m[/tex]
If we subtract 8m on both sides of the equation, we have:
[tex]2m-6-8m = 8m-8m\\-6m-6 = 0[/tex]
Adding 6 to both sides of the equation:
[tex]-6m-6 + 6 = + 6\\-6m = 6[/tex]
Dividing between -6 on both sides of the equation:
[tex]\frac {-6m} {6} = \frac {6} {6}\\-m = 1[/tex]
So:
[tex]m = -1[/tex]
If we want to know the value of 3m, then:
[tex]3m = 3 (-1) = - 3[/tex]
Answer:
Option C
