The point-slope form:
[tex]y-y_1=m(x-x_1)[/tex]
9.
We have:
[tex](8,\ 3)\to x_1=8,\ y_1=3\\m=5[/tex]
Substitute:
[tex]\boxed{y-3=5(x-8)}[/tex]
10.
We have:
[tex](-3,\ -5)\to x_1=-3,\ y_1=-5\\m=-\dfrac{2}{5}[/tex]
Substitute:
[tex]y-(-5)=-\dfrac{2}{5}(x-(-3))\\\\\boxed{y+5=-\dfrac{2}{5}(x+3)}[/tex]
