ddmonsterhigh
ddmonsterhigh ddmonsterhigh
  • 13-10-2018
  • Mathematics
contestada

Evaluate

4
E (2n-1)
n=1

Evaluate 4 E 2n1 n1 class=

Respuesta :

jimrgrant1 jimrgrant1
  • 13-10-2018

16

the simplest way to evaluate is to substitute n = 1, 2, 3, 4 into the expression and sum the terms

= [(2 × 1) - 1 ] + [(2 × 2) - 1 ] + [(2 × 3) - 1] + [(2 × 4) - 1]

= 1 + 3 + 5 + 7 = 16


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