Respuesta :

[tex]\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ b=5\\ A=13.2 \end{cases}\implies 13.2=\cfrac{1}{2}(5)(h)\implies 26.4=5h \\\\\\ \cfrac{26.4}{5}=h\implies 5.28=h[/tex]