bbygirlmaddie
bbygirlmaddie
15-06-2018
Mathematics
contestada
I need help please!!!!
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gmany
gmany
15-06-2018
[tex]\left(\dfrac{w^{15}}{w^5}\right)^4=\left(w^{15-5}\right)^4=\left(w^{10}\right)^4=w^{10\cdot4}=w^{40}\\\\\text{Answer:}\ \boxed{w^{40}}\\\\\text{Used:}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\\left(a^n\right)^m=a^{n\cdot m}[/tex]
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tdpuppies14
tdpuppies14
15-06-2018
Let's work this problem from inside the parentheses.
([tex] \frac{ w^{15} }{ w^{5} } [/tex] simplifies to [tex] w^{10} [/tex]
Now we have
[tex](w^{10})^{4} [/tex] which simplifies to [tex] w^{40} [/tex]
Final Answer: [tex] w^{40} [/tex]
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