cymeria cymeria
  • 14-06-2018
  • Mathematics
contestada

If r(x)=2-x^2 and w(x)=x-2, what is the range of (w*r)(x)

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altavistard
altavistard altavistard
  • 14-06-2018
First, find the product (w*r)(x):  (w*r)(x) = (x-2)*[2-x^2] = 2x - x^3 - 4 + 2x^2

This is a cubing function.  Since the sign of the cube-of-x term is negative, the graph will begin in Quadrant II and pass through Quadrant IV.  There are no limits on y.  Thus, the range is (-infinity, +infinity).

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