lhernand19 lhernand19
  • 12-06-2018
  • Mathematics
contestada

In Triangle XYZ, XZ = YZ and mZ = 74°. The longest side of the triangle is: A. XZ B. YZ C. XY D. XM

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calculista
calculista calculista
  • 22-06-2018
see the attached picture to better understand the problem

we know that
if  XZ = YZ 
then
XYZ is an isosceles triangle
m 
∠ Z=74°
m ∠ X= m ∠ Y
m ∠ X=(180°-74°)/2-----> m ∠ X=53°

applying the law of sines
XZ/sin 53°=XY/sin 74°
XZ=(sin 53°/sin 74°)*XY
XZ=0.83*XY
therefore
XZ < XY  or XY > XZ

the answer is
The longest side of the triangle is XY
Ver imagen calculista
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