interstellarmads interstellarmads
  • 13-05-2018
  • Mathematics
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what is the vertex form of y=x^2+16x+71 with steps please ?

what is the vertex form of yx216x71 with steps please class=

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jdoe0001 jdoe0001
  • 13-05-2018
[tex]\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ \begin{array}{llcccl} y = & 1x^2& +16x& +71\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array} \qquad \left(-\cfrac{ b}{2 a}\quad ,\quad c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{16}{2(1)}~~,~~71-\cfrac{16^2}{4(1)} \right)\implies (-8~~,~~71-64)\implies (-8~,~7)[/tex]
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