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kooldude0400oyfxya kooldude0400oyfxya
  • 11-05-2018
  • Mathematics
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Need help with this question: Write the equation of the parabola with focus (5,2) and directrix x=1

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mkryukova19 mkryukova19
  • 11-05-2018
Directrix  is x =1, so it is horizontal parabola.Vertex is between the focus and directrix on equal distance 5-x=x-1, 2x=6,
x=3. y -coordinate of the vertex for this parabola equals y-coordinate of the focus.
Vertex (3,2).

Focus has x=5 >1, so it is directed to the right.[tex](y-y_{0})^{2}=4p(x-x_{0}) \\(y-2)^{2}=4p (x-3) p is a distance between vertex and focus, and equals abs(p)=abs(5-3)= 2 \\(y-2)^{2}=(4*2) (x-3) \\(y-2)^{2}= 8 (x-3) [/tex]




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