If (√3 +i)¹⁰⁰ = 2⁹⁹ (p + iq), then p and q are roots of the equation :
a) x² - (√3 -1)x - √3 = 0
b) x² + (√3 +1)x + √3 = 0
c) x² + (√3 -1)x - √3 = 0
d) x² - (√3 +1)x + √3 = 0