Given function if f(x) = 2^(x), When strength is equal to 8 pascals, f(x) = 8 Therefore, 8 = 2^(x) Taking log on both sides: ln8 = ln2^(x) ln8 = xln2 or x = ln8/ln2 x = ㏑₂8 Hence, the required function is x = ㏑₂8.