Daisiasade13
Daisiasade13 Daisiasade13
  • 11-07-2017
  • Mathematics
contestada

What are the discontinuities of the function f(x) = the quantity of x squared plus 6 x plus 9, all over 3 x plus 15.?

Respuesta :

jimthompson5910 jimthompson5910
  • 11-07-2017
Factor: (x^2+6x+9)/(3x+15) = ((x+3)(x+3))/(3(x+5))

No factors cancel, so the discontinuity leads to a vertical asymptote. In this case, the vertical asymptote is x = -5 because this makes the denominator equal to zero. To find this value, set the denominator equal to 0 and solve for x

3(x+5) = 0
x+5 = 0
x = -5
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milliebobbybrown milliebobbybrown
  • 14-07-2017
3x+15=0
3x=-15
x=-5
 you just set the denominator to 0 and solve for x 

Answer Link

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