colbyferrell7 colbyferrell7
  • 14-05-2018
  • Mathematics
contestada

Simplify sin q + cosq cotq.

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gmany
gmany gmany
  • 15-05-2018
[tex]\sin q+\cos q\cot q=\sin q+\cos q\cdot\dfrac{\cos q}{\sin q}=\sin q+\dfrac{\cos^2q}{\sin q}\\\\=\dfrac{sin^2q}{\sin q}+\dfrac{\cos^2q}{\sin q}=\dfrac{\sin^2q+\cos^2q}{\sin q}=\dfrac{1}{\sin q}=\csc q\\\\Used:\\\cot q=\dfrac{\cos q}{\sin q}\\\\\sin^2q+\cos^2q=1\\\\\csc q=\dfrac{1}{\sin q}[/tex]
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mannysls0417
mannysls0417 mannysls0417
  • 02-06-2021

Answer:

D

Step-by-step explanation:

trust

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